3/x^2+2x=10/2x^2

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Solution for 3/x^2+2x=10/2x^2 equation: 



3/x^2+2x=10/2x^2

We move all terms to the left:

3/x^2+2x-(10/2x^2)=0



Domain of the equation: x^2!=0

x^2!=0/

x^2!=√0

x!=0

x∈R





Domain of the equation: 2x^2)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

2x+3/x^2-(10/2x^2)=0

We get rid of parentheses

2x+3/x^2-10/2x^2=0

We calculate fractions

We do not support expression: x^4

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